It is known that the consumption of dust per 100 kg of sinter mine is 12 kg, the amount of coke powder is 7.5 kg, the consumption of ore is X kg, and the consumption of limestone is Y kg. The sinter is required to contain FeO = 18.8%, alkalinity R = 1.20; chemical composition of raw materials.
Solution: Find X and Y must list two equations, one is the FeO equilibrium equation and the other is the alkalinity equilibrium equation.
(1) FeO equilibrium equation The weight loss due to carbon combustion, sulfur oxidation, carbonate decomposition, etc. during sintering is a.
Then the weight loss of the mixed mine a x = 0.05 × 0.9 + 0.96 = 1.005%
Dust weight reduction

The above calculation does not consider reducing the loss of iron ore, sintered desulfurization rate of 90%, fixed carbon by burning, Mn 3 O 4 made entirely of MnO (carried out as Mn 3 O 4 + CO = 3MnO + CO 2 reaction, this The deoxygenation of the reaction is
Provided the sintering process due to changes in oxidation and reduction of oxygen O is changed, the X + Y + 12 + 7.5-
aO = 100 becomes
O change =X+Y+19.5-100-0.01X-0.427Y-12×0.081-7.5×0.848
=0.99X+0.573Y-87.84
FeO from the addition reaction can be varied in the following lists work well becomes O:

Whether the number of O variants ore oxidation or reduction of FeO to 1 kilogram of oxygen changes correspondingly change O / 2FeO = 16/2 × 72 = 1/9 kilogram FeO, / the sintering per 100 kg:

(1) Equation 0.99X+0.573Y-87.84=-0.002X+1.84
0.992X+0.573Y=89.68 (2)[next]
(2) According to the balance of alkalinity, the following formula can be listed:

Solution (2) and (4) X = 71.34 kg Y = 33.23 kg D = 12.0 kg K = 7.5 kg per 100 kg of sintered ore consumption dry material amount is 124.07 kg, burning, desulfurization, reduction and deoxidation a total of 24.07 In kilograms, the reduction of oxygen in the oxide is 1.7 kg. In the on-site batching calculation, the oxygen loss of manganese and iron oxide reduction is not considered, and the desulfurization reaction is not considered. The total error is about 1.88 kg, accounting for 1.5% of the total dry material. Therefore, in general, the on-site batching calculation can also meet the general calculation requirements.
If this calculation is not considered to sulfur, oxygen loss, it becomes O = 0
Then 0.99X+0.573Y=87.84 (5)
Solving (4) and (5) can find the X and Y values. This calculation can also be greatly simplified.
The above calculation is based on 100 kilograms of sintered ore, so after determining the fuel consumption, the composition of the sintered ore can be calculated. Compared to on-site batching calculations, coke breeze consumption refers to the consumption per 100 kg of sinter, while the former refers to the fixed carbon consumption of 100 kg of dry mix.
The above calculations do not specify the amount of Fe, Mn, MgO in the sinter. If the above components are required, then the third equation can be listed according to the iron balance, and the fourth equation is listed according to the balance of manganese, according to MgO. The balance lists the fifth equation. At this point, there must be two or more kinds of iron ore for the ingredients. It is assumed that the consumption of one ore in the mixture is X, and the consumption of another ore is Z (or several other mixed minerals). The third-party program based on iron balance is:
X(Fe%) X +Z(Fe%) Z +D(Fe%) D +Y(Fe%) Y +K(Fe%) K =(Fe) A (6)
Equations (2) and (4) should be supplemented with Z values, and then the equations (2), (4), and (6) can be used to obtain X, Y, and Z values.
Similarly, if manganese ore is added to the sinter and the manganese content in the sinter is specified, the fourth equation can be listed. If the manganese ore consumption is W, the equation is:
X(Mn%) X +(Mn%) Z +W(Mn%) W +Y(Mn%) Y +D(Mn%) D +K(Mn%) K =Mn A (7)
Equations (2), (4), and (6) should be supplemented with M values, and then four (4), (4), (6), and (7) simultaneous equations are obtained for X, Y, Z, and W.
In order to meet the requirements of sinter MgO, add Dolomite V and list the fifth equation:
X(MgO%) X +Z(MgO%) Z +W(MgO%) W +Y(MgO%) Y +D(MgO%) D +V(MgO%) V +K(MgO%) K =( MgO)A
Equations (2), (4), (6), and (7) should be supplemented with V, and then the above five simultaneous equations are solved to obtain the consumption of various raw materials.

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